AL2O3 - AL - AL2(SO4)3 - AL(OH)3 - AL2O3

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вопрос

The chemical reactions involved in the conversion of aluminum metal (Al) to aluminum sulfate (Al₂(SO₄)₃) can be represented as follows:

Reaction of aluminum with oxygen to form aluminum oxide (Al₂O₃):
2 Al + 3/2 O₂ → Al₂O₃

Dissolution of aluminum oxide in sulfuric acid to form aluminum sulfate:
Al₂O₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂O

Precipitation of aluminum hydroxide from aluminum sulfate solution:
Al₂(SO₄)₃ + 6 H₂O → 2 Al(OH)₃ + 3 H₂SO₄

Dehydration of aluminum hydroxide to form aluminum oxide:
2 Al(OH)₃ → Al₂O₃ + 3 H₂O

Therefore, the overall reaction starting from aluminum metal and ending with aluminum oxide can be represented as:
2 Al + 3/2 O₂ + 6 H₂SO₄ + 6 H₂O → 2 Al₂(SO₄)₃ + 6 H₂O + 3 H₂SO₄ + 3 H₂O → 2 Al(OH)₃ + 3 H₂SO₄ + 3 H₂O → 2 Al₂O₃ + 3 H₂O

So, the reactions involved in the conversion of aluminum metal to aluminum oxide involve the formation of aluminum sulfate and aluminum hydroxide intermediates.