Log5(3x+19)=2

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вопрос

To solve this equation, we need to isolate the expression (3x + 19) inside the logarithm.

First, rewrite the equation using the exponential form of logarithm:
5^2 = 3x + 19

Simplify the exponential expression:
25 = 3x + 19

Subtract 19 from both sides:
6 = 3x

Divide by 3 to solve for x:
x = 2

Therefore, the solution to the equation Log5(3x + 19) = 2 is x = 2.